Are These Two Lines in Space Parallel?

AI Thread Summary
To determine if the lines r = i + 2j + t(i - k) and r = k + s(-i + k) are parallel, one must analyze their direction vectors. The first line has a direction vector of (1, 2, -1) and the second line has a direction vector of (-1, 0, 1). For the lines to be parallel, one direction vector must be a scalar multiple of the other. The discussion emphasizes the importance of identifying these vectors and applying the condition for parallelism in ℝ^3. Understanding these concepts is crucial for solving problems involving lines in three-dimensional space.
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Homework Statement


How are the two lines
r = i + 2j + t(i - k), and r = k + s(-i + k)
parallel?
t,s∈ℝ

Homework Equations


parametric vector equation of a line
r-r_0=tv

The Attempt at a Solution


Tried to find the conditions for lines to be parallel in ℝ^3.
 
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Suppose you have the equation as a constant vector ##\vec a## plus some parameter mutiplied by a second constant vector ##\vec b##. What scalar and vector operations can you do to it that would produce parallel lines?
 
A line in space can be written as \vec{r}= \vec{r_0}+ \vec{D}t where \vec{r_0} is the "position vector" of a single point on the line (the point where t= 0) and \vec{D} is the "direction vector" pointing in the direction of the line. Two lines are parallel if and only if one direction vector is a multiple of the other.

Edit: Some text removed by a mentor.
 
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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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