- #1
jayjay112
- 36
- 0
Aspect ratio of cylinder floating in water?
Hi,
Basically the question is:
What is the aspect ratio (h/d) for a cylinder of specific gravity 0.65 above which it will float vertically? (Note use GM = I/V - BG)
So i found a solution that is simliar and can help solve the problem. (please see attached)
Using this information would the ans be:
H/d = 0.65/sqrt(8 x 0.65)
I think the main problem is i don't fully understand the specific weights.
where it says h = specific weight /specific weight 2 x H
should specific weight /specific weight 2 be = 0.65
hope this makes sense thank you for your help
Hi,
Basically the question is:
What is the aspect ratio (h/d) for a cylinder of specific gravity 0.65 above which it will float vertically? (Note use GM = I/V - BG)
So i found a solution that is simliar and can help solve the problem. (please see attached)
Using this information would the ans be:
H/d = 0.65/sqrt(8 x 0.65)
I think the main problem is i don't fully understand the specific weights.
where it says h = specific weight /specific weight 2 x H
should specific weight /specific weight 2 be = 0.65
hope this makes sense thank you for your help
