[Astrophysics] Star luminosity-radius-temperature problem

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The discussion centers on solving a homework problem related to the luminosity-radius-temperature relationship of a Cepheid variable star. The initial confusion arises from the use of logarithmic equations versus direct calculations of luminosity ratios. The participant initially questions why logarithmic methods are necessary, as they seem to yield different results from direct calculations. Ultimately, they resolve the issue by recognizing the inverse nature of the magnitude scale, which clarifies their calculations. The problem is successfully solved using both approaches.
Andrev
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Hi!

Homework Statement



The light variation of a Cepheid is 2 mag,if its effective temperature at maximum luminosity is
6000K, while at minimum is 5000K, please estimate the ratio of its maximum and minimum
radius.

Homework Equations



$$\Delta m=-2,5lg\frac{L_{min}}{L_{max}}$$
$$lg\frac{L_{min}}{L_{max}}=2lg\frac{R_{min}}{R_{max}}+4lg\frac{L_{min}}{L_{max}}$$

The Attempt at a Solution



Well, actually I should solve the problem with those two formulas above. My question is: why I can not just calculate the $$\frac{L_{min}}{L_{max}}$$ and solve the $$\frac{L_{min}}{L_{max}}=\frac{4\pi R_{min}^2 \cdot T_{min}^4\cdot \sigma}{4\pi R_{max}^2 \cdot T_{max}^4\cdot \sigma}$$ equation? Why I have to calculate with the lgs? As I studied the problem it looked for me that these two methods are equal but I got different results.

Thanks in advance,


Andrev
 
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Sorry for spamming the forum with this I solved it on my own:

Of course I can calculate with the form without lgs too. I missed the calculation at the beginning: I forgot that the magnitude scale is inverse, so $$-0.4\cdot (m_1-m_2)=-0.4 \cdot \Delta m <0$$ It is ok now. Andrev
 
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