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Atomic E of a girl

If some girl weighs 100 pounds or 45.45 kg

E=mc[tex]^2[/tex]

Energy = (45.45) x (3 x 10[tex]^8[/tex])[tex]^2[/tex]

My answer was 4.9 x 10[tex]^1^8[/tex] J of E. But it's been a while and I'm not confident. Is that wrong?


thanks
 
Last edited:
That should be right. Why do you need to know? Are you planning to put the girl through nulcear fission...?
 
391
2
What are you doing? [tex]5^9[/tex]?

I'll assume you made a mistake, the answer is [tex]4.0905 * 10^{18}[/tex].
 
Ok thanks, 4.9 x 10[tex]^1^8[/tex] J of E.
 
391
2
NO! 4.09 x [tex]10^{18}[/tex], that zero is a huge difference.
 
Ok, thanks for your forbearance candyman.

Thanks a million.
 

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