Homework Help: Atomic E of a girl

1. Jun 16, 2005

Vincent Vega

If some girl weighs 100 pounds or 45.45 kg

E=mc$$^2$$

Energy = (45.45) x (3 x 10$$^8$$)$$^2$$

My answer was 4.9 x 10$$^1^8$$ J of E. But it's been a while and I'm not confident. Is that wrong?

thanks

Last edited: Jun 16, 2005
2. Jun 16, 2005

WhirlwindMonk

That should be right. Why do you need to know? Are you planning to put the girl through nulcear fission...?

3. Jun 16, 2005

theCandyman

What are you doing? $$5^9$$?

I'll assume you made a mistake, the answer is $$4.0905 * 10^{18}$$.

4. Jun 16, 2005

Vincent Vega

Ok thanks, 4.9 x 10$$^1^8$$ J of E.

5. Jun 16, 2005

theCandyman

NO! 4.09 x $$10^{18}$$, that zero is a huge difference.

6. Jun 16, 2005

Vincent Vega

Ok, thanks for your forbearance candyman.

Thanks a million.