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Atomic E of a girl

  1. Jun 16, 2005 #1
    If some girl weighs 100 pounds or 45.45 kg

    E=mc[tex]^2[/tex]

    Energy = (45.45) x (3 x 10[tex]^8[/tex])[tex]^2[/tex]

    My answer was 4.9 x 10[tex]^1^8[/tex] J of E. But it's been a while and I'm not confident. Is that wrong?


    thanks
     
    Last edited: Jun 16, 2005
  2. jcsd
  3. Jun 16, 2005 #2
    That should be right. Why do you need to know? Are you planning to put the girl through nulcear fission...?
     
  4. Jun 16, 2005 #3
    What are you doing? [tex]5^9[/tex]?

    I'll assume you made a mistake, the answer is [tex]4.0905 * 10^{18}[/tex].
     
  5. Jun 16, 2005 #4
    Ok thanks, 4.9 x 10[tex]^1^8[/tex] J of E.
     
  6. Jun 16, 2005 #5
    NO! 4.09 x [tex]10^{18}[/tex], that zero is a huge difference.
     
  7. Jun 16, 2005 #6
    Ok, thanks for your forbearance candyman.

    Thanks a million.
     
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