Atomic E of a girl

Vincent Vega

If some girl weighs 100 pounds or 45.45 kg

E=mc$$^2$$

Energy = (45.45) x (3 x 10$$^8$$)$$^2$$

My answer was 4.9 x 10$$^1^8$$ J of E. But it's been a while and I'm not confident. Is that wrong?

thanks

Last edited:
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WhirlwindMonk

That should be right. Why do you need to know? Are you planning to put the girl through nulcear fission...?

theCandyman

What are you doing? $$5^9$$?

I'll assume you made a mistake, the answer is $$4.0905 * 10^{18}$$.

Vincent Vega

Ok thanks, 4.9 x 10$$^1^8$$ J of E.

theCandyman

NO! 4.09 x $$10^{18}$$, that zero is a huge difference.

Vincent Vega

Ok, thanks for your forbearance candyman.

Thanks a million.

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