Average force applied by baseball on glove

AI Thread Summary
A 0.140-kg baseball traveling at 45.0 m/s strikes a catcher's mitt, which recoils backward 11.0 cm. To find the average force applied by the ball on the glove, the acceleration is calculated using the equation vf^2 = vi^2 - 2ad, resulting in an acceleration of 9205 m/s². This acceleration is then used in the formula F = ma, yielding a force of 1,289 N. The calculated force is considered high, but it reflects the significant force required to stop a baseball in such a short distance. The discussion emphasizes the physics behind the impact and the resulting force experienced by the glove.
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Homework Statement


A 0.140-kg baseball traveling 45.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 11.0 cm. What was the average force applied by the ball on the glove?


Homework Equations



F=ma ?

The Attempt at a Solution



It is the whole "backward 11.0 cm" part that confuses me.
 
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Clearly, the question is how can you find acceleration?

Hint: if the ball is initially traveling at 45 m/s, and the ball comes to rest after 11 cm, what equation can you use to find acceleration?
 
Okay, so I used the equation vf^2=vi^2-2ad.
0= 45^2 - 2*a*.11m
I ended up with 9205 m/s/s as the acceleration.

After plugging it into F=ma, I got 1,289N as the force. It seems too high.
Thanks by the way.
 
I got 1,289N as the force. It seems too high.

Excellent. That's what I got too. And, think about it. A baseball traveling 45 m/s comes to rest in only 11 cm! It takes a tremendous amount of force to stop it!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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