Average force of friction help

AI Thread Summary
To calculate the average force of friction on a wood block propelled by an elastic band, the frictional force can be determined by measuring the force applied while pulling the block. If the block was not accelerated during the pull, the force measured (8N) equals the frictional force opposing the motion. This relationship is based on Newton's first law, which states that no acceleration means no net force. The discussion also raises questions about whether kinetic energy should be considered and if timing the block's motion would help find its velocity. Understanding these principles is crucial for solving the problem accurately.
hockey45
Messages
4
Reaction score
0

Homework Statement


hi guys,
i am having trouble with this problem.
Calculate the average force of friction acting on a wood block as it is propelled along the floor by an elastic band ?

my solution and my ideas:
What does it mean by average froce of friction?
I first weighed the piece of wood to find its mass. i then used a Newton scale and pulled the elastic band 60 cm and found the force of friction which was 8n. is this force applied(8n)?did i measure the force correctly of the elastic.?i have no idea where to go from here. is there any kinetic energy involved? do i use Ek=1/2 mv^2. any suggestions would be helpful. do i time the wodeen block after i let it go and find the velocity. i am sure it is uniform acceleration.
thank you.
 
Physics news on Phys.org
Welcome to PF Hockey.

If you did not accelerate the block while pulling it along the floor the reading on the scale should be the same as the frictional force opposing the motion of the block. We can deduce this from Newton's first law - no acceleration implies no resultant force (along the direction of the floor). This implies that the pulling force and frictional force was the same magnitude but acted in opposite directions.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top