Find the average kinetic energy in kJ/mol (including all degrees of freedom) of one mole of ethane at 410K.
1/2Mu^s = kT/2
u= avg. velocity
N=degrees of freedom
The Attempt at a Solution
C2H6 degrees of freedom - 3n-6 = 18
(18/2)(1.380x10^-23 j/k)(410K)= 5.09e^20J
not sure how to get to KJ/mol from here.