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## Homework Statement

Find the average kinetic energy in kJ/mol (including all degrees of freedom) of one mole of ethane at 410K.

## Homework Equations

1/2Mu^s = kT/2

u= avg. velocity

E=n/2kT

N=degrees of freedom

## The Attempt at a Solution

C2H6 degrees of freedom - 3n-6 = 18

(18/2)(1.380x10^-23 j/k)(410K)= 5.09e^20J

not sure how to get to KJ/mol from here.