1. The problem statement, all variables and given/known data Find the average kinetic energy in kJ/mol (including all degrees of freedom) of one mole of ethane at 410K. 2. Relevant equations 1/2Mu^s = kT/2 u= avg. velocity E=n/2kT N=degrees of freedom 3. The attempt at a solution C2H6 degrees of freedom - 3n-6 = 18 (18/2)(1.380x10^-23 j/k)(410K)= 5.09e^20J not sure how to get to KJ/mol from here.