- #1
XPX1
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- 0
On your wedding day you leave for the church 36 minutes before the ceremony is to begin, which should be plenty of time since the church is only 9.0 miles away. On the way, however, you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 18 minutes is only 5.0 mi/h. What average speed do you need for the rest of the trip to get you to the church on time?
I have tried to complete this problem several times, and I have failed, it is getting pretty frustrating, here is what I have done.
Average Speed = [Distance][Time]
18 minutes / 5 mi/h = 3.6 miles traveled?
36-18 = 18 minutes more to travel 5.4 miles!
Now there is 5.4 miles left to be traveled. How in the heck do I figure out what my average speed needs to be to travel this within 18 minutes!?
Im seriously confused and lost, please help!
I have tried to complete this problem several times, and I have failed, it is getting pretty frustrating, here is what I have done.
Average Speed = [Distance][Time]
18 minutes / 5 mi/h = 3.6 miles traveled?
36-18 = 18 minutes more to travel 5.4 miles!
Now there is 5.4 miles left to be traveled. How in the heck do I figure out what my average speed needs to be to travel this within 18 minutes!?
Im seriously confused and lost, please help!
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