Average velocity question

  • Thread starter noname1
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  • #1
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I need to calculate the average velocity of

d= Et²+Ft+G over the interval [t1;t2]

I after resolving i get to this function

avg v = (E(t2)² + Ft2 - E(t1)² + Ft1) / (t2-t1)


my question is it possible to go any further than this?
 

Answers and Replies

  • #2
35,222
7,039
Your average velocity has an error. The Ft1 term in the numerator should be -Ft1. After you fix that, you can simplify your expression.

avg v = (E(t2)² + Ft2 - E(t1)² - Ft1) / (t2-t1)
= [E(t22 - t12) +F(t2 - t1)]/(t2 - t1)

Now factor (t2 - t1) out of each term in the numerator, and you can cancel with the same factor in the denominator.
 
  • #3
134
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yea i for got to distribute the - sign

would this be it?

[t2 - t1 (E(t2-t1) + F)]/ t2 - t1 and than the solution would be

(E(t2-t1) + F)

correct?
 
  • #5
134
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than like this

[E (t2-t1)(t2+t1) + F (t2-t1)] / t2-t1 =

than i can cancel the top (t2-t1) with the bottom giving

E (t2-t1) + F
 
  • #6
35,222
7,039
No again.

Also, you should write your expression this way: [E (t2-t1)(t2+t1) + F (t2-t1)] / (t2-t1)
 
  • #7
134
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crossed out the wrong one, i meant

[E (t2+t1) + F] correct?
 
Last edited:
  • #9
134
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and than for instantaneous i would take the derivative which is

2et² + f correct?
 
  • #10
35,222
7,039
Yes, but I would use the same letters as in the original problem.
v = 2Et2 + F
 
  • #11
134
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thanks for your help, now just have to figure out my other thread
 

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