Axis Rotation and Vector magnitude problem not sure if answers are right

AI Thread Summary
The discussion revolves around understanding vector direction and magnitude in a 3D context. The user is unsure how to label the direction of a vector in the xz-plane, particularly in the third quadrant, and questions the relevance of cardinal directions in this scenario. For the second problem, the user correctly decomposes vectors into components but confuses the labels for vectors B and C. Clarification is provided that cardinal directions are not necessary for 3D vectors, and a visual representation may help in understanding. The overall focus is on accurately determining vector direction and magnitude without relying on geographic terms.
BreakPoint
Messages
4
Reaction score
0
Hey guys I'm sort of new to this forum, but I heard it was good so I thought i'd post a few questions here

Homework Statement



The first question I have is not really a problem, but more of a question on the problem itself. I have two 3d vectors which are then subtracted to form a 3d vector in the xz plane, I need to find the direction of this vector, and it makes a 3,4,5 right triangle so i know the angle is 36.9 degrees, the question though is since its in the xz, would it still be S of W if it was in the 3rd quadrant? How would I label the direction of it? Would it even be in terms of North South East and West?
______________________
[PLAIN]http://img825.imageshack.us/img825/6527/lolphysics.png 2) Find the magnitude and direction of the sum R of the three vectors shown above; R = A + B + c. The vectors have the following magnitudes, A = 5.0 B = 7.9 and C = 8.0, express the direction of the vector sum by specifying the angle it makes with the positive x-axis with the counterclockwise angles taken to be positive

Homework Equations


The Attempt at a Solution



For the second one, I split them into components

A = 5i + 0j
B = 0i - 8j
C = -3.95i + 6.84j

to find the values for C, I used X = 7.9cos120 and Y = 7.9sin120

This gives an R value of 1.05i - 1.16j = R, which gives a magnitude of 1.56 and an angle of -47.8 degrees?
 
Last edited by a moderator:
Physics news on Phys.org
I'm comfused %^/

I'm having to struggle to understand the problem and I'm tired. I should go to bed.
 
Anyone?
 
Frankly, I wouldn't use N, S, E, and W designations, even with the xy-plane, unless you're talking about directions on the surface of the Earth. You just need to describe the direction so it makes sense to whomever is reading your work. You could draw a picture of the xz-plane with the vector and angle clearly labeled. Unlike with the xy-plane, there's no standard convention for specifying a direction as far as I know.

In the work for the second problem, you switched B and C from what the picture says, but your method is correct. I didn't check your actual numbers. I'll assume you punched everything into the calculator correctly.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top