Balancing Chemical Reactions: Isobutyric Acid + 2-Methoxyethanol

AI Thread Summary
The discussion centers on the reaction between isobutyric acid and 2-methoxyethanol, resulting in the formation of 2-methoxyethyl-2-methylpropanoate. Participants identify water as a by-product, formed from the -OH group of the acid and an H atom from the alcohol. The conversation highlights the need for conditions to favor the reaction's equilibrium, suggesting that an acid catalyst (H+) can facilitate the esterification process. The reaction is described as an acid-catalyzed dehydration of an alcohol, emphasizing the importance of adjusting conditions to optimize product yield.
jin.cao
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hi
i have the following reaction

isobutyric acid + 2-methoxyethanol <-> 2-methoxyethyl-2-methylpropanoate

but i don't know all of the by-products.

please help thanks

edit: i think is only water and some unreacted reactants?
 
Last edited:
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Acid is RCOOH and the alcohol is R'OH. Yes water will be a by-product. But how do you get water from this? (The -OH from the acid and the H from the alcohol bond together to form the water) What you are left with will form the other product.(btw were there any conditions for this reaction?)
 
Last edited:
no, because i am suppose to make procedure to create the product
so i will have to change the condition to shift equilibrium to the right side i guess...

why?
 
Because an acid and alcohol react to give ester and water in the presence of H+ as a catalyst.
 
thanks for confirm, rock
 
Just to name what your doing (basically acid catyzed dehydration of an alcohol is what your doing).
 
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