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Balancing Equation using redox reactions?

  1. Dec 1, 2009 #1
    OF2 --> F- + O2 + H2O

    OF2 --> F-

    2H+ +OF2 --> 2F- + H2O

    2H+ +OF2 + 4e- --> 2F- + H2O

    This is as far as I can get. I dont know how to do the other half of the redox since the equation would be:

    OF2 --> O2 + H2O

    What do I do here? Maybe Im not setting this up correctly?
     
  2. jcsd
  3. Dec 1, 2009 #2

    Borek

    User Avatar

    Staff: Mentor

    Please elaborate a little bit.

    Are you expected to use oxidation numbers or half reactions?

    Anything about conditions - low pH, high pH, just hydrolysis in water?

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  4. Dec 1, 2009 #3
    The problem states:

    "Balance the following redox reaction:

    In basic solution, oxygen difluoride reacts to produce fluoride ion, oxygen, and water."

    I figured out one way of doing it by just adding H2O, H^+ ions, and OH^- ions to either side and balancing it, but I want to know how to do it using half reactions.
     
  5. Dec 1, 2009 #4

    Borek

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    Staff: Mentor

    Assume OH- is being oxidized to O2 and water.

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