Balancing Equation using redox reactions?

  • Thread starter r_swayze
  • Start date
  • #1
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OF2 --> F- + O2 + H2O

OF2 --> F-

2H+ +OF2 --> 2F- + H2O

2H+ +OF2 + 4e- --> 2F- + H2O

This is as far as I can get. I dont know how to do the other half of the redox since the equation would be:

OF2 --> O2 + H2O

What do I do here? Maybe Im not setting this up correctly?
 

Answers and Replies

  • #2
Borek
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Please elaborate a little bit.

Are you expected to use oxidation numbers or half reactions?

Anything about conditions - low pH, high pH, just hydrolysis in water?

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  • #3
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The problem states:

"Balance the following redox reaction:

In basic solution, oxygen difluoride reacts to produce fluoride ion, oxygen, and water."

I figured out one way of doing it by just adding H2O, H^+ ions, and OH^- ions to either side and balancing it, but I want to know how to do it using half reactions.
 
  • #4
Borek
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28,702
3,190
Assume OH- is being oxidized to O2 and water.

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