- #1

peeballs

- 13

- 0

- Homework Statement
- What is the apparent pO2 (atm) in equilibrium with a pE governed by the sulfate/sulfide redox buffer when

(SO4

2-) = 10x (HS-) at paH 8.2? Use constants from Table 8.6a, pg. 465, assume I=0.

- Relevant Equations
- K = Products/Reactants

I've written out the half reaction

8e

and I know the logK = 4.25 (that's the constant mentioned in the prompt)

I've written out the equilibrium statement of 10^4.25 = ([x^1/8]*[H2O^1/2])/([10x^1/8]*[e-]*[(10^-8.2)^9/8]

However, from there, it seems like I have two unknowns - the X, and the e-, which I'm solving for. I don't know of any formulas that would be useful here and I was specifically told to use this expression to solve it.

Thanks

8e

^{-}+ 9H^{+}+ SO_{4}^{2-}= HS^{-}+ 4H_{2}Oand I know the logK = 4.25 (that's the constant mentioned in the prompt)

I've written out the equilibrium statement of 10^4.25 = ([x^1/8]*[H2O^1/2])/([10x^1/8]*[e-]*[(10^-8.2)^9/8]

However, from there, it seems like I have two unknowns - the X, and the e-, which I'm solving for. I don't know of any formulas that would be useful here and I was specifically told to use this expression to solve it.

Thanks