Balancing magnetic forces on rods

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To balance the magnetic forces on two parallel rods carrying currents in opposite directions, the mass of the upper rod must counteract the magnetic force exerted by the lower rod. The magnetic force can be calculated using the formula F=ILxB, where B represents the magnetic field strength. To determine the magnetic field strength, Biot-Savart's law or Ampere's law should be referenced. It is recommended to consult a textbook for detailed explanations on the forces between long parallel current-carrying wires. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement


If two parallel rods are placed 1mm apart, with one directly above the other, each carrying a current I in opposite directions, of length L what is the mass of the upper rod as to balance the force

Homework Equations


F=ILxB[/B]

The Attempt at a Solution


I have little idea of how to go about attempting this solution, thankyou! [/B]
 
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You need to assume the lower wire is held in a fixed position. It exerts a magnetic force ##IL\times B## on the upper wire.
 
Mister T said:
You need to assume the lower wire is held in a fixed position. It exerts a magnetic force ##IL\times B## on the upper wire.
Thankyou, but how do you work the magnetic field strength?
 
Will Freedic said:
Thankyou, but how do you work the magnetic field strength?
Biot-Savart's law or Ampere's law will be useful here.
 
Will Freedic said:
Thankyou, but how do you work the magnetic field strength?

I suggest you look in a textbook. There should be a section on force between long parallel current-carrying wires.
 
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