[SOLVED] Balky Cow (Forces) 1. The problem statement, all variables and given/known data A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn door, the cow walks from x = 0 to x = 6.9 m as you apply a force with x-component F_x = -[20.0N + (3.0N/m x]. How much work does the force you apply do on the cow during this displacement? 3. The attempt at a solution Given that: F_x = -[20.0N + (3.0N/m x] Displacement of 6.9 F_x = -[20.0N + (3.0N/m (6.9)] = -40.7N F_xo = -[20.0N + (3.0N/m (0)] = -20 N w= k2-k1 k = 1/2mv^2 W = F*s W = (-40.7-20) * (6.9m) = 418.83 :( Solution is: -209J why?