Ball in Free-Fall: Find Final Speed

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Homework Statement



A ball of mass m = 8 kg is dropped from rest at a height h = 13.9 m above the ground. Ignore air resistance.

(a)If the ball is being released with a downward speed 4.9 m/s initially, what will be its final speed when it hits the table 0.7 m below the release point?

(b) If the ball is being thrown upwards instead with the same speed 4.9 m/s, what is the final speed when it hits the table?

Homework Equations



Kf + Ugf = Ki + Ugi

The Attempt at a Solution


vf = sqrt(v(initial)^2 + 2g(h - y))
I just plugged in numbers and got 16.8 for part (a) and I plugged in numbers for part (b) and got 17.3. Also, for part (b), I substituted y=0 because I chose the y-axis to start at the bottom where the hand would be.
 
on Phys.org
To be clear. The ball is released at 13.9m and it hits the table at .7m?

And the initial velocity is 4.9m/s.

What does dropped from rest mean when you have an initial velocity given?
 
vf = sqrt(v(initial)^2 + 2g(h - y))
In the first part the distance traveled by the ball is only 0.7m.
 
Ignore that released from rest part.
 

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