Banked Curve Simple Conceptual Problem

AI Thread Summary
The problem involves a car navigating a banked curve at 110 km/h on a highway designed for 85 km/h with a 15-degree angle. The horizontal component of the normal force acts in the same direction as the centripetal force, which is directed inward toward the center of the curve. The initial confusion about the answer choices was clarified, confirming that the correct answer is that the horizontal component aligns with the centripetal force. It was emphasized that any mass not moving in a straight line experiences centripetal acceleration, which is consistent with Newton's laws. Understanding these forces is crucial for analyzing motion on banked curves.
Fireworks
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Homework Statement


Curve on highway, 15 degrees, designed for 85 km/h and car goes 110 km/hr. Horizontal component of normal force on car is:

a. in same direction as the centrifugal force
b. parallel to the road and towards the inside of the curve
c. in the same direction as the normal force
d. parallel to the road and towards the outside of the curve

Homework Equations


Conceptual problem

The Attempt at a Solution


I believe the answer is C, but I have to justify my answer and don't fully understand it. I think the horizontal component and the centripetal force point down the curve, but I am not completely sure.
 
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Centripetal force always points inward toward the center of curvature of the path. Are there more choices? Choice 'c.' is not correct.
 
I mistyped the answers, answer c is supposed to be: in the same direction as the centripetal force. And that is what I think it should be, but.. still could use some explanation help.
 
Fireworks said:
I mistyped the answers, answer c is supposed to be: in the same direction as the centripetal force. And that is what I think it should be, but.. still could use some explanation help.
Yes, C is correct, this figure should help:

http://hyperphysics.phy-astr.gsu.edu/HBASE/mechanics/carbank.html#c1

Any mass not moving in a straight line is centripetaly accelerated inward toward the center of the path of curvature, a_c = v^2/r, giving rise to a centripetal force in that direction, per Newton's 2nd Law, F_c =mv^2/r. This is true even if the speed of the object along the curved path is not constant.
 
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