Basic force with static friction problem

AI Thread Summary
To determine the resultant downhill force acting on a 70-kg skier on a 20-degree slope with a 15 N air resistance, the weight of the skier (approximately 700 N) must be broken down into its x and y components. The friction force, calculated using the coefficient of friction (0.09) and the normal force, also plays a critical role in the overall dynamics. The skier's weight creates a component acting down the slope, while air resistance and friction oppose this motion. The resultant force is found by summing the downhill force components and subtracting the opposing forces. Understanding these forces is essential for solving the problem accurately.
Ering
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Homework Statement



A 70-kg skier is in a tuck position and moving down a 20-degree hill. Air resistance applies a resultant force of 15 N against the movement of the skier. The coefficient of friction between the skis and the snow is 0.09. What is the resultant downhill force acting on the skier?

Homework Equations



Force = friction coefficient x normal force

The Attempt at a Solution



I know you have to break down the force into its x and y components. So making a right triangle with the weight (~700 N: 70kg x 10 m/s2) as the hypotenuse and 70 degrees (90 - the given 20 degrees) as the angle. But after doing that, I'm not sure where to go from there. Is the resultant force also your x-component in the right triangle?
 
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Ering said:
Is the resultant force also your x-component in the right triangle?
The resultant force in a given direction is the sum of all the components that are in that direction of the applied forces. What applied forces have components in the direction of interest?
 

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