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Basic help with PH

  1. Jun 4, 2009 #1
    1. The problem statement, all variables and given/known data
    We add 0.535 g of NaOH to 100.0 mL of water at 25degrees. What is [H3O+] in this solution at 25degrees?

    hey guys, ive practiced these types of questions alot, but ive never came accross one like this before. i tried writing equations and i got this 2NaOH+2H20>>2Na+2H30, but im stuck at the next step. anyhelp would be good. thanks

    ANSWER=7.48 x 10-14 M

    (p.s) if anyone could sit down with me on msn or something for 20minutes ive got about 15 basic question i need help with (ive got the answers). thanks
     
  2. jcsd
  3. Jun 4, 2009 #2

    symbolipoint

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    If that NaOH concentration is not too excessive for the model, you can try finding expected [OH-] and then use pH + pOH = 14
     
  4. Jun 4, 2009 #3

    Borek

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  5. Jun 4, 2009 #4
    ta, could you help me write the equation then because i cant get it to balance good? tnaks
     
  6. Jun 4, 2009 #5

    Borek

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    Your equation won't have H+ in it.

    Check the page I have lined to. To start you have to calculate [OH-].
     
  7. Jun 4, 2009 #6
    can i just write it like this..NaOH>Na+OH
     
  8. Jun 4, 2009 #7

    Borek

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    Don't ignore charges, these are ions. But otherwise you are on the right track, this is just a simple dissociation.
     
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