(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Integrate [tex]\int\sin 6x + 3\cos 5x dx[/tex]

2. Relevant equations

3. The attempt at a solution

The way I was taught was the 'u' substitution method.

I know that [tex]\int\sin u du = -\cos u + C[/tex] and I know that [tex]\int\cos u du = \sin u + C[/tex]

Here's what I've done so far

[tex]\int\sin 6x + 3\cos 5x dx[/tex]

[tex]\int\sin 6x dx + 3\int\cos 5x dx[/tex]

u = 6x; u = 5x

du = 6dx; du = 5dx

du/6 = dx; du/5 = dx

[tex]\frac{1}{6}\int\sin u du + \frac{3}{5}\int\cos u du[/tex]

Am I on the right track?

Thanks!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Basic Integration win sin and cos

**Physics Forums | Science Articles, Homework Help, Discussion**