Basis for Plane Perpendicular to a Line

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Homework Statement


Let L be the line in R^3 spanned by v1=(1,1,1)

Find a basis (v2,v3) for the plane perpendicular to L, and verify that B=(v1,v2,v3) is a basis for R^3.


Homework Equations





The Attempt at a Solution


I know that if two vectors are perpendicular or orthogonal that their dot product is equal to zero. However, I am not sure how to find a plane that is perpendicular to a vector.
 
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Hint: If you cross v1 with anything not parallel to it you will get a vector v2 perpendicular to v1. What direction will v2 cross v1 have?
 
You could also solve the equation

\begin{pmatrix}1 & 1 & 1\end{pmatrix}\begin{pmatrix}x \\ y \\ z\end{pmatrix} = 0

You'll get a two-dimensional solution from which you can read off two basis vectors.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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