Bead attached to a spring and moving along a horizontal wire

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Homework Help Overview

The problem involves a bead of mass m moving along a frictionless horizontal wire, attached to a spring with stiffness k and natural length l0. The spring is fixed at one end to a point A above the wire, creating a scenario where the potential energy function U(x) needs to be determined based on the bead's position x.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the potential energy function U(x) but questions the book's solution, suggesting that only the x-component of the spring's force should be considered. Other participants raise points about energy conservation and the implications of the spring's behavior when released, indicating a potential disagreement on the correct formulation.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the potential energy function. Some guidance has been offered regarding the relationship between the two expressions for U(x), suggesting they may differ by a constant. There is no explicit consensus on the correctness of either approach yet.

Contextual Notes

Participants are navigating assumptions about the spring's behavior and the implications of energy conservation in a frictionless environment. The original poster's concern about the relevance of the x-component of the force is a focal point of the discussion.

beowulf.geata
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I'm self-studying an introductory book on mathematical methods and models and came across the following problem:

1. A bead of mass m is threaded onto a frictionless horizontal wire. The bead is attached to a model spring of stiffness k and natural length l0, whose other end is fixed to a point A at a vertical distance h from the wire (where h > l0). The position x of the bead is measured from the point on the wire closest to A. Find the potential energy function U(x).

Homework Equations



I'm rather puzzled by the solution given in the book, which claims that since the length of the spring is (h2+x2)1/2 and its extension is (h2+x2)1/2 - l0, then U(x) = (1/2)k((h2+x2)1/2 - l0)2.

The Attempt at a Solution



I think that's incorrect because only the x-component of the force exerted by the spring on the bead is relevant to the calculation of U(x). The x-component is -k(l-l0)cos[itex]\theta[/itex], where l = (h2+x2)1/2 and cos[itex]\theta[/itex] = x/(h2+x2)1/2. Hence, U(x) is -[itex]\int[/itex](-kx + kl0x/(h2+x2)1/2)dx. Is this correct?
 
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Humm. Interesting question. I'm not sure I can answer it. At first thought you are correct, but then ...

With the spring stretched the energy stored in the spring will be that calculated in the book. What happens to the energy when the spring is released? Where does it go if you apply conservation of energy? The wire is frictionless so as far as I can see all the energy ends up in the bead (eg not some fraction of that due to the Cosθ issue you raise).

So I conclude the book is correct but I'm willing to be convinced you are right and the book is wrong.
 
See if you can show that both expressions are correct, although they might differ by an additive constant.
 
The integral should evaluate to

kx2/2 - kl0(h2 + x2)1/2 + C.

Hence, the difference between my solution and the book's is:

kx2/2 - kl0(h2 + x2)1/2 + C - (k(h2 + x2)1/2l0 + (1/2)kh2 + (1/2)kx2 - (1/2)kl02)
= C - (1/2)kh2 + (1/2)kl02,

so the two solutions do appear to differ by a constant...
 

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