- #1
FishieKissie06
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A friend in another city tells you that she has a pair of organ pipes, one open at both ends, the other open at one end only. In addition, she has determined that the beat frequency caused by the second-lowest frequency of each pipe is equal to the beat frequency caused by the ninth-lowest frequency of each pipe. Her challenge to you is to calculate the length of the organ pipe that is open at both ends, given that the length of the other pipe is 1.10 m. Note that there are two possible answers to this question. List them both, in the order indicated below.
so in other words fbeat = f1 - f2 where... fbeat 2= fbeat 9... where 2f1 - 2f2 = 9f1 - 9f2 ... and i know the length of the closed end pipe which is 1.10 how am i suppose to consider even solving this or where I can get the frequency of a closed end pipe at n=2...
so in other words fbeat = f1 - f2 where... fbeat 2= fbeat 9... where 2f1 - 2f2 = 9f1 - 9f2 ... and i know the length of the closed end pipe which is 1.10 how am i suppose to consider even solving this or where I can get the frequency of a closed end pipe at n=2...