Beginner Question About Series Parallel

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Discussion Overview

The discussion revolves around identifying whether circuit elements are in series or parallel, particularly in the context of calculating total resistance in a circuit. Participants explore definitions, provide examples, and clarify concepts related to circuit analysis.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asserts that two elements are in parallel if they share two extraordinary nodes, while another participant agrees with this definition but questions its application in a specific example.
  • Another participant suggests that to find the Thevenin equivalent, one must short-circuit the voltage source and redraw the circuit for clarity.
  • There is a discussion about the configuration of resistors, with one participant stating that R3 is in series with (R1 || R2) because they do not share the same two extraordinary nodes.
  • A participant challenges a drawing that incorrectly shows R1 being shorted out, clarifying that shorting the voltage source involves replacing it with a wire.
  • One participant provides a drawing to illustrate their understanding, stating that R3 is in series with (R1 || R4) and that the entire arrangement is parallel with R4, while R5 is in series with the whole setup.
  • Another participant corrects the previous statement about the configuration, indicating that it should refer to (R1 || R2) instead of (R1 || R4).
  • A participant provides a general definition of series and parallel connections, explaining that elements are in series if the current through them is the same and in parallel if they are connected at both ends, sharing the same voltage.
  • One participant notes that the total resistance can differ based on the perspective of the circuit being analyzed, providing an example of how R1 and R2 appear in parallel when looking from the output, but the input resistance is calculated differently.

Areas of Agreement / Disagreement

Participants express both agreement and disagreement on various points, particularly regarding the configuration of resistors and the definitions of series and parallel connections. There is no consensus on the correct drawing or the total resistance calculations, indicating that multiple competing views remain.

Contextual Notes

Limitations include potential misunderstandings in circuit drawings and the dependence on specific definitions of series and parallel connections. The discussion also highlights the complexity of analyzing circuits from different perspectives, which may lead to different interpretations of the same configuration.

dlacombe13
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How exactly do you tell if two elements are in series or parallel? I know that if two elements share two of the same extraordinary nodes then they are in parallel:
dcc390ca-f757-461c-8b72-f05ffcdab258_zpspyyb4l1g.png

But in this example I do not see that. I know for certain that the answer for Rt is:
[ ( (R1 || R2) + R3) || R4 ] + R5

27d5b21a-409c-4061-8986-7477e0735f50_zpskdnedivc.png
 
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To find RThevenin you must short-circuit the voltage source. Do that and redraw. See if things make sense then.
 
Oh okay, that makes sense now, it would look like this:
seriesparallel_zpslo5erpld.png

And so the reason R3 is in series with (R1 || R2 ) is because they do not share the same two extraordinary nodes, right?
 
The drawing is not quite right. You are showing that R1 is being "shorted out" which is not the case. When you short the voltage source, you simply replace it with a wire.
 
You are right about why R3 is in series with R1||R2.

Here's what I mean about your drawing:
Code:
 +--R1---+--...
 |       |
 |       |
(|)      R2
 |       |
 |       |
 +-------+--...

Which is the same as:

 +-------+--...
 |       |
 |       |
 R1      R2
 |       |
 |       |
 +-------+--...
 
Right, that makes sense, here is my drawing now, which I think is correct:
seriesparallel_zps9r7wnvra.png

So in this drawing, the reason R3 is in series with (R1 || R4) and then that whole quantity (enclosed in the box) is parallel with R4 since they both share the Green and Blue nodes. R5 is then in series with all of this since it does not share any other nodes with the circuit other than the Green one.
 
Instead of "(R1 || R4)", you mean to say (R1 || R2).

Other than that, you are correct!
 
dlacombe13 said:
How exactly do you tell if two elements are in series or parallel?

If all the current that flows through one of them MUST flow through the other one too, they are in series. Current through them is the same.

If they are solidly connected together at both ends, they are in parallel. Voltage across them is the same.

Note that it is possible for them to be both in series and in parallel at the same time.
Draw yourself the simple circuit consisting of just a battery and lightbulb. It meets both those criteria.

old jim
 
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dlacombe13 said:
How exactly do you tell if two elements are in series or parallel?
But in this example I do not see that. I know for certain that the answer for Rt is:
[ ( (R1 || R2) + R3) || R4 ] + R5

27d5b21a-409c-4061-8986-7477e0735f50_zpskdnedivc.png

Please note that in this example both resistors R1 and R2 appear in parallel because it was your task to find the total resistance while looking into the circuit from the output.
The situation is quite different for the total input resistance of the circuit as measured at the + node of the battery.
In this case we have Rin=R1 + [(R3+R4)||R2]
The resistor R5 has no influence as long as the output nodes are not loaded by any other resistor.
 

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