What's the total amount of resistance in this kind of circuit?

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Discussion Overview

The discussion revolves around calculating the total resistance in a specific circuit configuration involving multiple resistors and additional connections labeled K12 and K34. Participants explore different methods for analyzing the circuit, considering both series and parallel arrangements of the resistors.

Discussion Character

  • Homework-related, Technical explanation, Exploratory

Main Points Raised

  • One participant suggests that resistors R1 and R2 are in parallel, as well as R3 and R4, and R5 and R6, leading to a proposed formula for total resistance.
  • Another participant challenges the initial assumption that R1, R2, and R3 can be in series due to the presence of a third connection that may affect current flow.
  • A later post indicates that the circuit can be simplified by treating pairs of resistors as parallel connections, but notes complications could arise if additional resistors were involved in the connections K1 and K2.

Areas of Agreement / Disagreement

Participants express differing views on how to treat the connections and the arrangement of resistors, indicating that there is no consensus on the correct approach to calculating the total resistance.

Contextual Notes

Participants highlight potential complications arising from the connections K12 and K34, particularly if they involve resistors with non-zero values, which could affect the overall analysis.

Who May Find This Useful

This discussion may be useful for students or individuals studying circuit analysis, particularly those dealing with complex resistor configurations and seeking to understand the implications of additional connections in circuits.

Reneee
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TL;DR
Homework Statement::
(for another Problem) I just need to know what the total amound of resistance would be for the following circuit?
Divider.png

I am not sure how to treat the extra connections K12 and K34.
My first guess would be (R1 and R2) are parallel and so are (R3 and R4) and (R5 and R6) ,so
R_{total}= {R1*R2} /{R1+R2} +...

Or maybe the behaviour is like this:
(R1, R3, R5) are in series , and (R2 R4 R6) are, thus
R_{total}= (R1+R3+R5)*(R2+R4+R6) / (R1+R3+R5)+(R2+R4+R6)?
 
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Your first method is correct. (R1, R2, R3) cannot be in series because where they connect to each other there's a third connection that could potentially add or subtract current from the connection point.
 
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alright, thank you!
 
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You're very welcome!
 
Reneee said:
Summary:: Homework Statement::
(for another Problem) I just need to know what the total amound of resistance would be for the following circuit?

I am not sure how to treat the extra connections K12 and K34.
Wired together, as in the diagram, the pairs are at the same potential so you have three pairs of parallel connected resistors. Easy when you can simplify a circuit in this way.
The problems would arise if K1 and K2 were connected by resistors with non zero value.
 

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