Bernoulli's Equation of water tower

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SUMMARY

The discussion centers on applying Bernoulli's Equation to a water tower scenario, specifically calculating the absolute pressure at point 1 when the valve is opened and determining the volume flow rate. The equation used is p1 + density(g)(y) + 0.5(density)(v)^2 = p2 + density(g)(y) + 0.5(density)(v)^2. Given that point 1 is open to the atmosphere, the absolute pressure at that point is 101,000 Pa. The effective cross-sectional area of the valve opening is 2.09 x 10-2 m2, which is critical for calculating the volume flow rate.

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Homework Statement


The water tower in the drawing is drained by a pipe that extends to the ground. The flow is nonviscous.

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(b) What is the absolute pressure at point 1 when the valve is opened and the water is flowing? Assume that the water speed at point 2 is negligible.

(c) Assuming the effective cross-sectional area of the valve opening is 2.09 multiplied by 10-2 m2, find the volume flow rate at point 1.



Homework Equations





The Attempt at a Solution


For part b:

p1 +density(g)(y) + .5(density)(v)^2 = p2 +density(g)(y) + .5(density)(v)^2
p1 + 0 + .5(1000)v^2 = 101000 + 1000(9.8)(15)

I have two variables p1 and v, so how can I solve this?
 

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Anyone?
 
The fact that point 1 is essentially open to the atmosphere (hint, hint) dictates what the pressure is there.
 

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