Beta decay problems, not getting the right answer

AI Thread Summary
The discussion focuses on solving beta decay problems involving the calculation of neutrino energy and kinetic energy of emitted electrons. For phosphorus-32 decaying to sulfur-32, the calculated neutrino energy is incorrectly found to be 0.80 MeV instead of the correct 0.25 MeV. In the case of boron-12 decaying to carbon-12, the maximum kinetic energy of the emitted electron is miscalculated as 13 MeV instead of 12.8 MeV. For nitrogen-12's beta-plus decay, the neutrino energy is incorrectly calculated as 7 MeV rather than the correct 5.8 MeV. The poster expresses confusion over the calculation methods and seeks a step-by-step solution, particularly regarding the mass of emitted electrons.
crosbykins
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Homework Statement



a) What is the energy of the neutrino, if a phosphorus-32 atom (31.97390
u) beta-decays into a sulphur-32 atom (31.97207 u), and the kinetic energy of the
accompanying electron is 0.90 MeV? (answer: 0.25 MeV)

b) A boron-12 atom (12.01435 u) beta-decays into a carbon-12 atom (12.00000 u).
What is the maximum kinetic energy of the emitted electron? (answer: 12.8 MeV)

c) In the β+ decay of nitrogen-12 (12.01864 u) into carbon-12 (12.00000 u), a
positron with energy of 11.0 MeV is emitted. What is the energy of the electron
neutrino? (answer: 5.8 MeV)



Homework Equations



** equations not really used

The Attempt at a Solution



a)

Δ m = 31.97390u – 31.97207u
= 1.83*10^-3 u

(1.83*10^-3 u) (931 MeV)
= 1.70 MeV

1.70 MeV – 0.90MeV
=.80 MeV

Therefore, the energy of the neutrino is .80 MeV.

b)
Δ m = 12.01435u – 12.00000u
= .01435u

(.01435u)( 931 MeV)
=13 MeV

Therefore, the maximum kinetic energy is 13 MeV.

c)

Δ m = 12.01864u - 12.00000u
= .01864u

(.01864u) ( 931 MeV)
=17 MeV

17 MeV – 11.0MeV
= 7MeV

Therefore, the energy of the neutrino is 7MeV.

***right, so the answers i got are all wrong, i think the method in which I'm doing this is wrong, but i can't find information in my book on how to do it the correct way... a step-by-step solution would really really be appreaciated, thanks :)
 
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