What Are the Longest and Shortest Wavelengths of the Pfund Series in Hydrogen?

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The Pfund series in hydrogen involves electron transitions to the n=5 energy level, producing specific spectral lines. To determine the longest and shortest wavelengths, one must identify the energy levels from which electrons transition. The longest wavelength corresponds to the smallest energy jump, while the shortest wavelength corresponds to the largest energy jump. The Pfund series lines are found in the infrared region of the electromagnetic spectrum. Understanding these transitions is crucial for analyzing hydrogen's line spectrum.
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Homework Statement


in the line spectrum of atomic hydrogen there is also a group of lines known as the pfund series. these lines are produced when the electrons, excited to high energy levels, make transitions to the n=5 level.
Determine (a) the longest wavelength and the (b) shortest wavelength in this series. (c) what region in the electromagnetic spectrum in which these lines are found.


Homework Equations


En=E1/n^2


The Attempt at a Solution



i think i have to find the energy levels it could have started from
and then find the biggest jump and smallest made. but i don't know how to find the energy level it started from
 
Last edited:
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Welcome to PF,

HINT: What energy does the de Broglie wavelength correspond to? Where did this energy come from?
 
appologies

Hootenanny said:
Welcome to PF,

HINT: What energy does the de Broglie wavelength correspond to? Where did this energy come from?

sorry i copied the wrong problem
 
mandymanny said:
i think i have to find the energy levels it could have started from
and then find the biggest jump and smallest made. but i don't know how to find the energy level it started from
The pfund series starts from n=5, and includes transitions to higher energy levels, as stated in the question.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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