How Do You Calculate Velocity in Physics Problems?

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The discussion centers on calculating velocity in a physics problem where an object moves at a constant velocity of 5.6 m/s and undergoes an angular displacement of 9.5 rad. It is noted that the question lacks clarity on the type of velocity being referenced, leading to the assumption that it is tangential. The constant velocity implies no acceleration, making the question potentially invalid unless it seeks angular speed, which is calculated as 1.56 rad/s. Additionally, the total force exerted is interpreted as centripetal force, calculated using the formula Fc = (Vt^2)/r, resulting in 8.71 N. The discussion emphasizes the need for clearer specifications in physics problems to avoid confusion.
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Big physics question (really urgent)

http://img135.imageshack.us/img135/6500/physicsdt8.jpg

I solved a,b, need help with the rest, how do u get velocity ??

Please help. This needs to be submitted soon
 
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This question is very vague.
It says that the object is moving at a constant velocity of 5.6m/s.
First of all it does not specify what kind of velocity; Angular or Tangential?
Lets assume tangential...

The question ask what the objects velocity is, yet it already gave the CONSTANT velocity as 5.6m/s. The only change the question states that the object makes is an angular displacement of 9.5rad, which brings no reason for a change in velocity unless the specific time is given, which it is not, so one would assume that the tangential velocity remains constant as the question previously stated. And if this is true than the object would experience no acceleration at all so that question does not appear valid. However if it is asking for the Angular speed after a dis. of 9.5rad then:

9.5rad = 34.2m
5.6m = 1s
34.2m = 6.107s
9.5rad= 6.107s
so...
w = 9.5rad/6.107s = 1.56 rad/s

However acceleration is still nonexistent.

Then it ask for the total force exerted on the object, again not specifying what kind of force. Let's again assume it means Centripetal force. If 5.6m/s is referring to tangential acc. then we find:

Fc = (Vt^2)/r
Fc = 5.6^2/3.6= 8.71 N
 
for the angle you can convert it to degrees by multiplying it by 180/pi then take the sin of that and multiply it by 3.6 to find position vector j.

for velocity it should be the original velocity

for acceleration it is centripetal acceleration

for force it is centripetal acceleration multiplied by mass
 
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