Binary w/ black hole - semi-major axis?

AI Thread Summary
In an X-ray binary system with a B2 main-sequence star and an unseen black hole, the separation of 20 million km corresponds to the sum of the semi-major axes of both bodies around their barycenter. To apply Kepler's Version of Newton's Third Law, this separation can be used directly as the value for 'a' in the formula. The orbital period of 4 days is also necessary for calculations. Clarification was provided that 'a' represents the total distance between the two objects, not just one semi-major axis. Understanding this distinction is crucial for accurately determining the sum of the masses in the system.
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Say I have an X-ray binary system of a B2 main-sequence star with an unseen companion (i.e., black hole). They have a separation of 20 million km and an orbital period of 4 days.

How do I figure out what the semi-major axis is? I need it for the formula for Kepler's Version of Newton's Third Law:

M_{1} + M_{2} = (4π²)÷G × (a³)÷(p²)
where G is the gravitational constant, p is the period (which is given to me) and a is the semi-major axis. My question asks to find the sum of the masses, so I need to plug something in for a in the equation to get that answer. Can I just use the 20 million km separation?

Thanks! :)
 
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mbradar2 said:
Say I have an X-ray binary system of a B2 main-sequence star with an unseen companion (i.e., black hole). They have a separation of 20 million km and an orbital period of 4 days.

How do I figure out what the semi-major axis is? I need it for the formula for Kepler's Version of Newton's Third Law:

M_{1} + M_{2} = (4π²)÷G × (a³)÷(p²)
where G is the gravitational constant, p is the period (which is given to me) and a is the semi-major axis. My question asks to find the sum of the masses, so I need to plug something in for a in the equation to get that answer. Can I just use the 20 million km separation?

Thanks! :)

In the formula you listed, 'a' is the sum of the semi-major axes of the orbits of the the two bodies around the barycenter. So in this case, it is equal to the separation between the two bodies.
 
Oh, it's the SUM of both semi-major axes? I thought it was just one, which is why I was confused.

Well, thanks for clearing that up! :)
 
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