How Does Electron Movement Affect Magnetic Fields in a Hydrogen Atom?

AI Thread Summary
The discussion focuses on calculating the magnetic field produced by an electron's motion in a hydrogen atom. The user initially applied the Biot-Savart law but made an error in their calculations, resulting in an incorrect magnetic field value of 1.99 T instead of the correct 12.5 T. The mistake was identified as omitting an additional 'r' in the denominator of the final expression. The correct formula for the magnetic field incorporates this additional factor, leading to the accurate calculation. Understanding the electron's circular motion and its impact on magnetic fields is crucial in atomic physics.
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Homework Statement


In a model of a hydrogen atom, an electron circles the proton at a distance of 5.29E-11 m with a speed of 2.19E6 m/s. Compute the magnitude of the magnetic field that this motion produces at the location of the proton.


Homework Equations


dB = (u/4pi*r^2) I ds x r(roof) (Biot-Savart's law)


The Attempt at a Solution


I did I = e*v/(2*pi*r) where e is electron charge and v is the velocity. I got I = .00105 A. I plug in that into B = uI/(4*pi*r) = 1.99 T but the answer is 12.5 T. What am I doing wrong? Thank you.
 
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There's one more 'r' in the denominator. The final expression is

\frac{\mu_{0}}{4\pi} \frac{ev}{r^2}.
 
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