Understanding BJT Emitter Resistance: Explained by Horowitz & Hill

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The discussion centers on the intrinsic emitter resistance (re) in BJTs as explained in Horowitz & Hill. Participants clarify that re represents the dynamic resistance of the base-emitter diode, typically placed in series with the emitter. However, in emitter follower circuits, it is often shown connected to ground, which helps achieve low output resistance. There is debate about the correct expression for output impedance, with suggestions that it should involve adjustments to the terms related to beta. Additionally, the importance of a pull-down resistor at the emitter output is emphasized to prevent floating voltages when no load is connected.
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Hey everyone,

Im currently reading Horowitz & Hill and am a little confused on the topic of the intrinsic emitter resistance (re). I understand that this resistance is essentially the dynamic resistance of the base-emitter diode.

I assumed that when analyzing a circuit this resistance should always be placed in series with the emitter. However H&H seem to place this resistance from the emitter to ground in the emitter followers they demonstrate.

In the case of the emitter follower circuit this makes sense because the low re means that the circuit will have a low output resistance as expected. I just don't understand why they placed it to ground.

The circuits in question are attached.
 

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What makes you think that the resistors from emitter to ground shown in the images are re, the intrinsic emitter resistance? They aren't labeled re.
 
I think you mean r'e or pronounced 'R prime E' or 'R E prime'. Summarized, R'e is the AC impedance of the base emitter junction. Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e].
 
You say:

"Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e]."

Shouldn't the "(beta*the base circuit impedance)" expression be something more like "(the base circuit impedance/beta)"? Actually, I think the "beta" should be "beta+1".
 
The Electrician said:
You say:

"Normally the output imedance of an emitter follower is Re (actual resistor from emitter to ground) in parallel with [(beta*the base circuit impedance) + r'e]."

Shouldn't the "(beta*the base circuit impedance)" expression be something more like "(the base circuit impedance/beta)"? Actually, I think the "beta" should be "beta+1".

Yes, my bad.
 
It is usually a good idea to have a pull-down resistor on the emitter output to keep the output potential from floating up to the base potential when the external load is not connected. It is absolutely necessary if the external load does not have a dc path to ground.
 
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