Block and wedge system all details

AI Thread Summary
A block resting on a frictionless wedge experiences a gravitational force component acting down the incline, specifically mgsin(alpha), which influences its motion. The wedge will also move due to the reaction force from the block, resulting in both the block and wedge accelerating. The acceleration of the block can be determined by resolving the forces acting on it, while the wedge's motion must be analyzed based on Newton's third law. A diagram illustrating the forces and accelerations for both the block and the wedge would clarify the interactions. Understanding these dynamics is essential for solving the problem effectively.
smartyrohan12
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Homework Statement


okay this isn't really a question, but i didnt knew where to post it, tell me if it has to be posted somewhere else. a pic of the diagram would help a lot.
A block is kept on the top of a wedge of angle alpha, can u explain what all happens, keeping all surfaces frictionless, what are their velocities and acceleration.


Homework Equations


I don't know


The Attempt at a Solution


i only know that a mgsin(alpha) will act on the block, nothing else..
 
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Draw a diagram.
Put in the forces acting on the block.
Resolve forces in components along the direction of motion and perpendicular to this direction.
 
but i want to know how will the wedge be affected as the surface is frictionless...
 
Draw a diagram and put in all the forces. It is good to make a contribution yourself first in line with the spirit of this forum.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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