Block collidining with a spring

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A 2.40 kg block collides with a spring (spring constant 400 N/m) and compresses it 5.00 cm, while experiencing a kinetic friction coefficient of 0.450. The main question is about calculating the work done by the spring in bringing the block to rest. Users suggest starting with the principle that the work done by the spring equals the change in potential energy. There is confusion regarding the integration of the spring force and friction, with requests for detailed explanations on the correct method. Clarification on the integration process is needed to resolve the confusion.
zhenyazh
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hi,
i am preparing for an exam and have a problem with the following question.
an image is attached.

A moving 2.40 kg block collides with a horizontal spring whose spring constant is 400 N/m.
The block compresses the spring a maximum distance of 5.00 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.450. What is the work done by the spring in bringing the block to rest?

i am confused. tried to integrate kx on the 0 until 0.05 didn't work.
tried the same minus the friction force on that area. didn't work.

could some one explain in detail how it is done here?

thanks
 

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you can start from the fact that the work done by a conservative force which in your case is a spring force equals to the change in potential energy ..


I hope now it is clear enough for you to start ..
 
zhenyazh said:
i am confused. tried to integrate kx on the 0 until 0.05 didn't work.
That should work just fine--show how you did the integration.
 

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