Box and friction distance problem?

In summary, the problem involves a box sliding up an incline at an angle of 17.0° with a coefficient of kinetic friction of 0.180. The box starts with an initial speed of 1.30 m/s at the bottom of the incline and the question asks for the distance the box travels before coming to rest. The solution involves finding the normal force and friction, adding in the component of gravity, and using kinematics to find the distance traveled.
  • #1
bman123
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0

Homework Statement


A box is sliding up an incline that makes an angle of 17.0° with respect to the horizontal. The coefficient of kinetic friction between the box and the surface of the incline is 0.180. The initial speed of the box at the bottom of the incline is 1.30 m/s. How far does the box travel along the incline before coming to rest?



Homework Equations


Ffr=(mu)(FN)



The Attempt at a Solution


I tried drawing a free body diagram and altering my x-axis to the incline but I can't seem to figure it out. Any help would be greatly appreciated. THanks!
 
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  • #2
Hi there!
It could always help, on your part, to post the drawings/sketches you've already made, so that one gauge where you stand...
Anyhow, you must notice that, as the box struggles against the incline, it is opposed by both gravity, and friction.
You must first find the normal force from the surface, and determine the friction, add to that the component of gravity resisting its movement, and that will be your acceleration.
Kinematics then leads to:
[itex]
\large
V^2 = {v_0}^2 + 2as
[/itex]
Where you seek- S, and V is known to be zero, when the object stops.
Try it,
Daniel
 

1. What is the "box and friction distance problem"?

The "box and friction distance problem" refers to a physics problem in which a box is placed on a horizontal surface with a certain coefficient of friction. The goal is to determine the distance the box will travel before coming to a stop, given its initial velocity and the force of friction acting on it.

2. How do you calculate the force of friction in the box and friction distance problem?

The force of friction can be calculated using the formula: F = μN, where μ is the coefficient of friction and N is the normal force. The normal force is equal to the weight of the box in this scenario, and can be calculated using the formula: N = mg, where m is the mass of the box and g is the acceleration due to gravity.

3. What factors can affect the distance the box travels in the box and friction distance problem?

The distance the box travels can be affected by the coefficient of friction, the initial velocity of the box, the mass of the box, and the surface on which the box is placed. Other factors such as air resistance and the shape of the box may also play a role.

4. How can the box and friction distance problem be solved?

The box and friction distance problem can be solved using the equations of motion, specifically the equation: d = v0t + 1/2at^2, where d is the distance traveled, v0 is the initial velocity, t is the time, and a is the acceleration. The acceleration can be calculated using the formula: a = (F - μN)/m.

5. Are there any real-world applications for the box and friction distance problem?

Yes, the box and friction distance problem has many real-world applications. For example, it can be used to calculate the stopping distance of a car on a road with a certain coefficient of friction. It can also be applied to the design of conveyor belts and other machinery that involves the movement of objects on a surface with friction.

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