Breaking point of rod under torsion

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Discussion Overview

The discussion centers on the breaking point of a steel rod subjected to torsion, specifically examining whether the rod will break at the fixed end or the movable end when increasing torsion is applied. The scope includes theoretical mechanics and stress analysis related to torsion and material failure.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the rod will break at one of the chamfered locations due to stress concentration, but questions whether it will be at the fixed or movable end.
  • Another participant argues that the rod does not 'know' which end is fixed and which is movable, implying it could break at either end.
  • A different viewpoint claims that the rod will break at the rotating end due to greater shear stress resulting from the rotation, contingent on the rod not being infinitely stiff.
  • There is a challenge to clarify whether the term "shear stress" or "shear strain" is more appropriate in the context of the discussion.
  • One participant emphasizes the importance of distinguishing between large rotations and large strains in mechanics, suggesting that the behavior of the rod is independent of the coordinate system used.

Areas of Agreement / Disagreement

Participants express differing views on where the rod will break, with no consensus reached. Some argue for the rotating end while others suggest either end is possible.

Contextual Notes

Participants note the significance of stress concentration and the material properties of the rod, but there are unresolved aspects regarding the definitions of shear stress and shear strain, as well as the implications of stiffness on the breaking point.

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A steel rod like the one shown in the attached picture is fixed from one side and increasing amount of torsion is applied on the other side. Eventually, the rod breaks. Now it will obviously break from one of the two chamfered locations, where the middle portion of the rod with the smaller diameter increases to turn into the larger diameter ends, due to the stress concentration effect. But from which of the two sides will it break; the fixed end or the movable (rotating) end?
 

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Everything else being equal, the rod doesn't 'know' which end is having torque applied and which is fixed, thus it can break at either end.
 
http://en.wikipedia.org/wiki/Torsion_(mechanics )
It will break at the turn end because its not infinitely stiff (if infinitely stiff you are correct Claws). The rotated end will have some rotation so greater shear stress.
 
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greater shear stress.

Don't you mean shear strain?
 
cloa513 said:
The rotated end will have some rotation so greater shear stress.

If you explain why you think that statement is true, we might be able to explain why you are wrong.

The behaviour of the rod does not depend on the coordinate system you use to describe it.

For any situation in mechanics where rotations are important, you need to be clear about the difference between large rotations and large strains.
 

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