- #1
Adarshaero
- 5
- 0
A bullet of 0.005 kg traveling at 20m/s penetrates deeply into a fixed target and is brought to rest in 0.01 sec. The distace through which it penetrates is:
I used,
acceleration= V/t
= 20/.01
a = 2000 m/sec sq
Distace covered = Ut+0.5 at^2
= 20*0.01+0.5*2000*(o.o1)^2
S= 30cm.
Is it correct or any other solution is possible..?
I used,
acceleration= V/t
= 20/.01
a = 2000 m/sec sq
Distace covered = Ut+0.5 at^2
= 20*0.01+0.5*2000*(o.o1)^2
S= 30cm.
Is it correct or any other solution is possible..?