Calc Required Torque & RPM for Automotive App

AI Thread Summary
To calculate the required torque to move a 12-tonne vehicle from a stationary position, the torque must equal the friction of all moving parts, which is not easily quantifiable without practical testing. When the vehicle is in first gear, the engine's torque must overcome this friction to initiate movement. The discussion highlights that the engine's torque measurements (230 Nm at 1000 rpm and 241 Nm at 1200 rpm) may be insufficient for such a heavy vehicle, especially considering drivetrain losses of around 30%. A practical method to determine the necessary torque is to use a spring scale to measure the force required to start moving the vehicle. Overall, the calculations are complex and depend on various factors, including drivetrain efficiency.
Rob
Messages
3
Reaction score
0
Hello
I am working on vehicle, for which i need to calculate following things

1. Required torque (Nm) to move vehicle from stationary position?
2. RPM of the engine at the time of torque mentioned in point number 1?

Available Input:
1. Vechile Weight(kg) - 4300
2. Engine Displacement - 3455
3. Gross Vechile Weight(kg) - 12990
4. Tyre Raduis (m) - 0.464
5. Gear Ratio 1st - 7.600
6. Gear Ratio 2nd - 3.7
7. Final gear Ratio - 6.142
8. Engine Max. Te(Nm) - 315 @ 1625RPM
9. Engine Torque = 230 Nm @ 1000 rpm , 241 Nm @ 1200 rpm (Actual Measurement)

Thanks,
 
Engineering news on Phys.org
Copied from your the identical question in this thread https://www.physicsforums.com/threads/calculate-motor-torque-requide-to-drive-a-cart.772433/

Please don't double up posts, it makes the forum messy.

billy_joule said:
"241 Nm @ 1200 rpm"

That gives a power of under 30kW, a third of the power of my last motorbike. Good luck shifting a 12 tonne vehicle with that. It's possible but probably not wise.

As for your questions:

1. Depends on the friction of all moving parts.
2. Zero. If the vehicle is stationary, so is the motor (unless you use a clutch).

Rob said:
Thanks for help

We are using dry friction clutch
Vehicle stationary and engine is idling, but when i put vehicle on 1st gear at what point of Torque@RPM vehicle start moving?

When the torque applied by the motor is equal to the friction of all moving parts.
There's no easy way of calculating this. Easiest way is probably to pull the stationary vehicle with a spring scale - the reading when the truck begins to move can be used to calculate the torque at the wheels required to move. Of course that ignores all the torque losses between the motor and the wheels which could be around 30%, it'll depend on the efficiency and condition of your drive train, this article is a good intro to drivetrain losses:

http://www.modified.com/tech/modp-1005-drivetrain-power-loss/
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top