Equilibrium Constant for Calcium Carbonate Reaction at 500 C

AI Thread Summary
The discussion centers on calculating the equilibrium constant for the reaction of calcium carbonate at 500 C, where the equilibrium pressure of carbon dioxide is 1.2 x 10^-3 atm. Participants clarify that for gas reactions, pressure can be used in place of concentration in the equilibrium constant expression. The relationship between pressure and molarity is highlighted, with the equation M = P/RT being referenced for conversions. There is some confusion about whether to use pressure or concentration, but it is ultimately established that pressure is applicable for gases in this context. The conversation emphasizes the importance of understanding these principles for accurate calculations.
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Calcium Carbonate is heated in a closed vessel, and an equilibrium is reached.

CaCO3 (s) <=> CaO(s) + CO2 (g)
At 500 C the equilibrium pressure of carbon dioxide is 1.2*10^-3 atm and at 1000 C it is 3.87 atm.
what is the equilibrium constant for this reaction at 500 C? :confused:
 
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Try posting your questions in the chemistry subforum here at PF (I don't have the time to help you at the moment).
 
I'm not really good at chemistry but isn't it 1.2*10^-3? The only gas around is CO2 so writing the equlibrium formula gives CO2's pressure. This probably isn't right but how to do it?
 
The equilibrium formula refers to concentration not pressure of a liquid. Is it the same for a gas? or is the pressure used in the case of a gas?
 
I think I got it right now. Since PV=nRT, P=MRT. Thus, M=P/RT. I think you can do the rest.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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