Calcualte water discharge of a pipeline at different heights

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To calculate the water discharge of an 8 km pipeline conveying water from a reservoir at 500 m to a treatment works at 425 m, Bernoulli's equation and mass conservation principles are applied. The initial velocity (U1) is zero due to the stationary reservoir. The pressure at both ends of the pipeline (p1 and p2) must be accurately computed to determine the velocity (u2) at the outlet. Initial calculations suggest a velocity of 54.24 m/s, but the expected answer is 38.36 m/s, leading to a discharge of 1.525 m³/s. Clarification is needed on the pressure calculations to resolve discrepancies in the results.
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A pipeline is 8 km long and is required to convey water from a reservoir, at 500 m
above datum, to the intake of a water treatment works at 425 m above datum. If
the pipe has a diameter of 225 mm, what is the discharge of water through the
pipe? The density of water is 1000 kg/m3.

relevant equations:

bernoullis Energy Conservation:

P1/ρg + u1^2/2g + z1 = p2/ρg + u2^2/2g + z2

mass conservation equation:

U1A1 = U2A2

Q1 = Q2




The Attempt at a Solution



U1 = 0 Since the resovoir is stationary,

p1 = ρgh p2 = ρgh

putting values into bernoullis:

4905000/9810 + 500 = 4169250/9810 + u2^2/19.62 + 425


150 = u2^2/19.62

u2^2 = 2943
√2943 = 54.24 m/s

at this point the answer should be: 38.36 m/s

and the final answer should be: Q = 1.525m^3/s

i am completely lost, any help would be massively appreciated!
 
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escobar147: What is the reservoir depth at the pipe inlet? And what is the reservoir depth (if any) at the pipe outlet? It currently appears you made a mistake in computing either pressure p1 or p2, or on both p1 and p2. Show how you computed p1 and p2, and why?
 
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