Calculate Acceleration Given V0 and X

  • Thread starter Thread starter LiiArch
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
The astronaut on planet Zog kicks a football with an initial velocity of 11.7 m/s, achieving a maximum distance of 90 m. To find the acceleration due to gravity (g), he calculates the optimal launch angle, which is 45 degrees, resulting in horizontal and vertical components of 7.78 m/s each. Using these values, he determines the time of flight to be approximately 11.6 seconds. Initially, he miscalculated the initial velocity, which affected his results, but after correcting it, he successfully finds g to be 1.34 m/s². This example illustrates the importance of accurate initial conditions in projectile motion calculations.
LiiArch
Messages
10
Reaction score
0

Homework Statement


An astronaut kicks a football on a level area of planet Zog. He kicks the ball repeatedly at a wide range of angles from nearly zero to almost 90 deg above the horizontal, but always as hard as he can which gives an initial velocity of 11.7 m/s. The astronaut notices that the maximum distance the ball lands away from him is 90 m. Armed with this information and because he mastered Physics 2048, he returns to his landing craft and quickly calculates the acceleration of gravity g on planet Zog. What is that value?

V0 = 11.7 m/s
X = 90 m
X0 = 0 m
Y0 = 0 m

All of the relevant equations I think I can use involve time, which is not given. So, I do not know where to begin. If I can figure out where to start, I think I can figure it out pretty easily.
 
Physics news on Phys.org
At what angle will the ball travel the maximum distance?

Think about that. The rest of the problem should follow naturally.
 
You have to go a little bit outside of plugging values into the kinematic equations.

Hint: The maximum distance the ball goes is 90m.

EDIT: Sid beat me to it.
 
Okay, that did get the ball rolling. I figured it was 45.0 degrees, so I calculated Vx and Vy.

Vx = 7.78 m/s
Vy = 7.78 m/s

Then I plugged in these values to this equation to find t:

X(t) = X0 + Vx0t
90 = 0 + 7.78t
11.6 s = t

So then I plug t = 11.6 s into this equation:

Y(t) = Y0 + Vy0t - 1/2(g)(t^2)
0 = 0 + 7.78(11.6) - 1/2(11.6^2)(g)
0 = 90.25 - 67.28g
67.28g = 90.25
g = 1.34 m/s^2

But, this is incorrect. :[
 
Are you sure you calculated the initial velocities correctly?
 
No I just realized that. For some reason I was putting 11 instead of 11.7 - silly me.

With new numbers, I got it right. Thanks guys!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top