Calculate Acceleration of Thrown Baseball: 5.98s, 1.2m from Rest

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To calculate the acceleration of a thrown baseball, first determine the initial velocity required for the ball to be in the air for 5.98 seconds. This involves using kinematic equations for constant acceleration. The acceleration produced by the person's arm can then be calculated based on the distance of 1.2 meters from rest. The discussion emphasizes the need to apply the correct equations for both the upward motion and the acceleration phase. Understanding these principles is crucial for solving the problem accurately.
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A person throws a baseball straight up (in the y direction). The ball is in the air for 5.98 seconds before it returns to the same height from where it was initially released. If the person when throwing the ball, generated a constant acceleration over a distance 1.2 m from rest, what is the acceleration produced by the person's arm in m/s2?

I guess you have to use a constant acceleration equation or a free fall equation, but I do not know which one.
 
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First of all find the initial velocity with which the ball is thrown up so that it will be in the air for 5.98 seconds.
Then find the acceleration of the arm which can produce this velocity with in the distance of 1.2 m.
 
Check out this link, it may help you------>media.wiley.com/product_data/excerpt/88/.../0471713988.pdf
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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