Calculate Angle C with Tail-Tip Method

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To calculate angle C in a triangle formed by two vectors using the tail-tip method, the law of cosines requires knowing the lengths of all three sides, which is not possible with only two sides and their angles. Without the resultant vector C, which is the sum of the two vectors, angle C cannot be determined. The discussion suggests using the law of sines as an alternative, but emphasizes that two sides and the included angle are necessary for calculations. To find the magnitude of vector C, one must sum the vertical and horizontal components of the two vectors. Ultimately, additional information about the vectors is needed to proceed with the calculations.
Confused one
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I have 2 vectors, which are plotted using the tail-tip method to form a non-right triangle.

Side A is vector 1, side B is vector 2, and side C is my resultant.
I know I can get angle C, but that's where I'm stuck.

How do you get angle C? In simple terms...:confused:
 
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It's a bit confusing to talk about "side C" and "angle C"! Standard notation is that the lengths of the three sides of the triangle are a, b, c and the angles opposite each are A, B, C respectively. If you know a, b, c, then use the cosine law to find C: c2= a2[/sup]+ b2- 2ab cos(C). Plug in a, b, c and solve for C.
 
I don't have c. I have a, b, and their degrees, but no c. I don't have A or B either.

I'm trying to sove for C, but I must have c before I can use the law of cosines.
 
how about law of sins

sin A / a = sin B / b = sin C / c
 
You orginally said "Side A is vector 1, side B is vector 2, and side C is my resultant" so it was reasonable to assume that you knew those 3 lengths. In vector problems, normally you know two vectors, say lengths a and b, and the angle between them, but that would be C which you say you don't know. If lengths a and b are the only values you have, you can't solve this: two parts of a triangle are not enough! What information do you have?
 
You have to understand that the resultant vector components are the sum of the adding vectors. Add the vertical component of the vector A to the vertical component of vector B. Then add the horizontal component of the vector A to horizontal component of vector B. Then you have the components of vector C and the magnitude of C = ((Ay + By)^2 + (Ax + Bx)^2)^1/2
 
Werg22 said:
You have to understand that the resultant vector components are the sum of the adding vectors. Add the vertical component of the vector A to the vertical component of vector B. Then add the horizontal component of the vector A to horizontal component of vector B. Then you have the components of vector C and the magnitude of C = ((Ay + By)^2 + (Ax + Bx)^2)^1/2

That's one way to do it. It may or may not be simpler than adding the vectors "geometrically". The question "Confused one" initially asked made it clear, I thought, that he was attempting to do this geometrically. I sure wish he would get back to us and tell us exactly what information he has to work with. I would have suggested that he find angle C by just subtracting the angles the the vectors make with some fixed line, but surely he wouldn't be having so much trouble if he were given the vectors like that.
 
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