Calculate Atomic Energy of a Girl (45.45 kg)

  • Thread starter Thread starter Vincent Vega
  • Start date Start date
  • Tags Tags
    Atomic Girl
AI Thread Summary
The discussion revolves around calculating the energy equivalent of a girl weighing 45.45 kg using Einstein's equation E=mc^2. The initial calculation yielded an energy value of 4.9 x 10^18 J, which was later corrected to 4.09 x 10^18 J due to a significant error in the exponent. Participants questioned the purpose of the calculation, humorously suggesting it might relate to nuclear fission. The conversation highlights the importance of precision in scientific calculations. Overall, the correct energy equivalent is confirmed to be 4.09 x 10^18 J.
Vincent Vega
Messages
42
Reaction score
0
If some girl weighs 100 pounds or 45.45 kg

E=mc^2

Energy = (45.45) x (3 x 10^8)^2

My answer was 4.9 x 10^1^8 J of E. But it's been a while and I'm not confident. Is that wrong?


thanks
 
Last edited:
Physics news on Phys.org
That should be right. Why do you need to know? Are you planning to put the girl through nulcear fission...?
 
What are you doing? 5^9?

I'll assume you made a mistake, the answer is 4.0905 * 10^{18}.
 
Ok thanks, 4.9 x 10^1^8 J of E.
 
NO! 4.09 x 10^{18}, that zero is a huge difference.
 
Ok, thanks for your forbearance candyman.

Thanks a million.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top