Calculate change in air pressure (Physics 101 type Q)

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To calculate the change in air pressure in a compressed hose, the volume decrease from 47.1 cubic inches to 44.7 cubic inches results in a 5.1% reduction in volume. This volume change leads to an increase in pressure of approximately 0.76 PSI, assuming the initial pressure is 15 PSI. A switch capable of detecting less than a 1 PSI increase is recommended for effective activation. It is also suggested to measure the rate of pressure change to account for temperature variations and potential leaks. Overall, the calculations and considerations presented are logical and correct for the scenario described.
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I'd like to calculate the change in air pressure within a long tube - like the driveway hoses at gas stations.

The static pressure is zero, a vehicle drives over the hose and the increase in pressure activates a switch. I'm trying to determine the proper switch size (in PSI).

So, here is my attempt to start solving this (simple) problem...
  • The hose is 1/2" (interior diameter) by 20 feet long. I calculate the cubic inches to be 47.1 (3.14 x 1/4 x 1/4 x 240 inches).
  • If a vehicle drives over the hose, (say 12" of hose is compressed flat, for simplicity), then the cubic inches become 44.7 (3.14 x 1/4 x 1/4 x 228 inches). (If the two wheels don't hit at the same time, this could certainly change the results...but let's just keep it simple for now - one wheel, evenly compressed hose.)
  • Volume of air decreases from 47.1 cubic in (CI) to 44.7 CI...how is this converted to a change in air pressure (assuming 47.1 was at 0 PSI)?

Thanks
 
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At constant temperature the pressure * volume stays the same.
So if you decrease the volume by 10% the pressure goes up by 10%.

ps. The pressure in the pipe is 15psi - the same as outside air.
The 'gauge pressure' (PSG), ie the extra internal pressure, is zero.
 
Just to make sure I got this right...
In my example, the volume (of air in a tube capped at both ends) decreases from 47.1 to 44.7 or 5.1%...
Then the pressure would have increased 0.76 PSI (15PSI x 5.1%)
And I would need a switch able to detect < 1PSI increase in pressure.
...sounds logical...is it correct?
 
Correct
Ideally you would like to measure a rate-of-change of pressure, then you don't have to worry about the absolute pressure in the pipe changing with temperature or slow leaks etc.
The change in pressure with time as a car rolls over it should be pretty noticeable.
 
Great!
Thanks for the help...and additional considerations (temp., leaks, etc...had not considered...yet!).
 
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