Calculate CM Speed of Rod on Compressed Spring

AI Thread Summary
The discussion revolves around calculating the speed of the center of mass (CM) of a uniform rod released from a compressed spring. The rod has a mass of 0.31 kg and a length of 0.45 m, pivoting at one end and moving through various angles. The initial angle is 57 degrees, and it stops at 107 degrees after passing through the horizontal position. Participants express confusion about how to approach the problem and note the absence of a necessary figure for clarity. The focus remains on finding the CM speed at the horizontal position.
Sumbhajee
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Homework Statement



A thin uniform rod has mass M = 0.31 kg and length L= 0.45 m. It has a pivot at one end and is at rest on a compressed spring as shown in (A). The rod is released from an angle θ1= 57o, and moves through its horizontal position at (B) and up to (C) where it stops with θ2 = 107o, and then falls back down. Friction at the pivot is negligible. Calculate the speed of the CM at (B).

http://schubert.tmcc.edu/res/msu/physicslib/msuphysicslib/21_Rot3_AngMom_Roll/graphics/prob32a_RodOnSpring.gif

Homework Equations





The Attempt at a Solution



Not sure where to start on this one. Thank you for your time and any help provided.
 
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Where is the figure? Problem is not clear without that.
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »

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