Calculate Electric Potential Change: +1 & -3 Micro-Coulombs

AI Thread Summary
To calculate the change in electric potential when moving a -3 micro-coulomb charge from 2 meters to 4 meters away from a +1 micro-coulomb charge, the relevant equation is delta V = - integral of E(x)dx. The negative charge's influence is not directly included in the integral because the electric potential is determined by the source charge, which is the +1 micro-coulomb charge. The potential is inversely proportional to the distance from the charge, meaning that as the distance increases, the potential decreases. Understanding this relationship simplifies the calculation, focusing on the distance rather than the magnitude of the second charge. The key takeaway is that only the source charge's effect on potential matters in this scenario.
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Homework Statement



There is a +1 micro-coulomb charge at the origin and a -3 micro-coulomb charge at 2 meters away along the x-axis. I am suppose to find the change in Voltage if second charge is moved to 4 meters away from the origin.

Homework Equations



I am thinking of using delta V= - integral of E(x)dx , where the limits of integration is from 2 to 4.

The Attempt at a Solution



i am not sure why the negative three micro-coulomb isn't included when using this equation. can someone explain why?
 
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Well I'll tell you're over complicating it. Pretty much the only equation you need is electric potential = somestuff / r

You don't even need to know what the somestuff is, only that potential is inversely proportional to r
 

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