Calculate forces on beam with hook

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To calculate the forces on a beam with a hook, one can proceed by analyzing the entire system for equilibrium, while also considering subsystems that may not be in equilibrium. The calculations involve determining moments at point A and resolving forces in both x and y directions. There is some confusion regarding the correct distances used in the moment calculations, particularly the lever arm length. It is emphasized that the moment of a force is influenced by the lever arm's length and the angle between the lever arm and the force. Both scalar and vector methods can be utilized to find the moment, depending on preference.
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Calculate forces on beam with "hook"

I have a beam which looks roughly like the attached file. The aim is to calculate forces in A and B. Would I have to look at AB and CDE independently, or could I proceed as "usual" by calculating the moment in A and proceed with forces calculation in x and y direction?
 

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You could proceed "as usual". The entire system must be in equilibrium, subsystems may not and typically will not be in equilibrium per se.
 


I've done the forces and moment calculations on the beam, but I'm a bit unsure if it's done correctly. Every force is working on the center lines according to the figure, so I might be missing something here. I'd appreciate it if someone could take a look at my calculations and perhaps give some input.
A better figure showing all the measurements is attached.ƩMA= 0 → B*6,3+F*sin 44,4*3,6 =0 (direction: counter clockwise.)
B*6,3+19,5*sin 44,4*3,6 =0
B= -7,796 kN

ƩFx=0 → Ax-F*cos44,4=0
Ax-19,5*cos 44,4=0
Ax-13,932=0
Ax= 13,932kN
ƩFy=0 → Ay+B-F*sin44,4=0
Ay+7,796-19,5*sin 44,4=0
Ay-5,847=0
Ay= 5,847
 

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Last edited:


How did you get "3.6" in ƩMA= 0 → B*6,3+F*sin 44,4*3,6 =0? The distance from A to E is not 3.6.
 


That's one of the things where I'm not sure if it's done correctly, but what I did was add 2,2 and 1,4. I suppose the height has to come into play somewhere, but I'm not sure how. Up until now I've only been doing calculations on regular beams without any sort of "protrusion".(Sorry, I don't know the correct English term for a beam like this.)
 


The moment of a force is the product of the "lever arm", the force's magnitude, and the sine of the angle between the lever arm and the force. The lever arm is the distance from the point around which the moment is taken to the point of the force's application. In this case, the lever arm is AE. You need to find its length and the angle between AE and the force.

Alternatively, the moment is defined as a vectorial product of the lever arm and the force, which allows you to get around without computing angles and lengths.

You can use either method.
 
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