Calculate Gravity Using Pendulum Experiment

  • Thread starter Thread starter Effitol840
  • Start date Start date
  • Tags Tags
    Gravity Pendulum
Click For Summary
To calculate gravity using a pendulum experiment, the period (T) of the pendulum is given by the equation T = π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. It is recommended to use the longest string possible to minimize the amplitude of oscillation, ensuring the approximation holds true for small angles. Conducting the experiment with different string lengths can provide more data, but maintaining a constant length may simplify the process. The accuracy of the results depends on adhering to the conditions of small oscillations. Further questions can be addressed as the experiment progresses.
Effitol840
Messages
16
Reaction score
0
Alright so here’s the problem. In lab we are supposed to come up with a way to figure out gravity using an experiment. The experiment that I came up with is to use a pendulum and find its period and then calculate the gravity. I know this is possible but I don’t know the equations. If anyone can help me out with the equations for this type of problem it would be much appreciated. Also, would it be better to do a few different string lengths or keep the string length constant?
 
Physics news on Phys.org
Effitol840 said:
Alright so here’s the problem. In lab we are supposed to come up with a way to figure out gravity using an experiment. The experiment that I came up with is to use a pendulum and find its period and then calculate the gravity. I know this is possible but I don’t know the equations. If anyone can help me out with the equations for this type of problem it would be much appreciated. Also, would it be better to do a few different string lengths or keep the string length constant?

The period of a simple pendulum is

T=\pi \sqrt{ \frac{L}{g}}

With L being the length of the pendulum.

I would use the longest string you possibly can.
 
Remember, that expression,

T=\pi \sqrt{ \frac{L}{g}}

is an approximation and is accurate only for small oscillations, where sin\theta \approx \theta

That's why you should use as long a string as possible, so as to keep the amplitude of oscillation as small as possible.
 
Thanks... I need to run the expirement again. If I have any more questions I'll be sure to ask.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
6
Views
984
Replies
3
Views
2K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
920