Calculate Inertia: What is the Mass of the Crate?

  • Thread starter Thread starter emily081715
  • Start date Start date
  • Tags Tags
    Energy Inertia
AI Thread Summary
The discussion centers on calculating the mass of a crate using principles of physics after a firecracker explosion. Participants emphasize the need for conservation of momentum and energy equations to solve for the crate's mass and the firecracker's speed post-explosion. It's noted that while the firecracker releases 9 J of energy, not all of it may convert to kinetic energy, suggesting assumptions about energy conversion should be made cautiously. The importance of correctly applying the equations without prematurely simplifying variables is highlighted. Overall, the conversation reflects a collaborative effort to approach the problem methodically.
emily081715
Messages
208
Reaction score
4

Homework Statement


A mysterious crate has shown up at your place of work, Firecracker Company, and you are told to measure its inertia. It is too heavy to lift, but it rolls smoothly on casters. Getting an inspiration, you lightly tape a 0.60-kg iron block to the side of the crate, slide a firecracker between the crate and the block, and light the fuse. When the firecracker explodes, the block goes one way and the crate rolls the other way. You measure the crate's speed to be 0.064 m/s by timing how long it takes to cross floor tiles. You look up the specifications of the firecracker and find that it releases 9 J of energy. That's all you need, and you quickly calculate the inertia of the crate.

Homework Equations


p=mv
k=1/2mv2

The Attempt at a Solution


i know the inertia is referring to the mass of the crate. will i need to use the chang in kinetic energy equation to solve for mass?
 
Physics news on Phys.org
Nice story. Good thing the crate wasn't full of firecrackers or pure gunpowder (not unthinkable in such a company...).
Teacher must have had a good time composing it. He doesn't tell you how much of the 9 J is converted to kinetic energy, but I guess you should assume 100%. So the crate comes away undented and undamaged.

Yess, the exercise wants the mass of the crate. Aside from your two equations you'll need a bit more: energy conservation, momentum conservation, to name some. Start your attempt at solution and post when stuck ...
 
emily081715 said:

Homework Statement


A mysterious crate has shown up at your place of work, Firecracker Company, and you are told to measure its inertia. It is too heavy to lift, but it rolls smoothly on casters. Getting an inspiration, you lightly tape a 0.60-kg iron block to the side of the crate, slide a firecracker between the crate and the block, and light the fuse. When the firecracker explodes, the block goes one way and the crate rolls the other way. You measure the crate's speed to be 0.064 m/s by timing how long it takes to cross floor tiles. You look up the specifications of the firecracker and find that it releases 9 J of energy. That's all you need, and you quickly calculate the inertia of the crate.

Homework Equations


p=mv
k=1/2mv2

The Attempt at a Solution


i know the inertia is referring to the mass of the crate. will i need to use the chang in kinetic energy equation to solve for mass?

Hey Emily! ;)

We have 2 unknowns: the mass of the mysterious crate, and the speed of the firecracker after the explosion.
To find them we need 2 equations.
Can we set up the equations for conservation of momentum and conservation of energy?
 
I like Serena said:
Hey Emily! ;)

We have 2 unknowns: the mass of the mysterious crate, and the speed of the firecracker after the explosion.
To find them we need 2 equations.
Can we set up the equations for conservation of momentum and conservation of energy?
mc(vci-vcf)=mb(vbf-vbi)
vci-vbi=vbf-vcf

would i be using theses? for the second equation i divided out mass and the 1/2 and rearranged a bit
 
emily081715 said:
mc(vci-vcf)=mb(vbf-vbi)
vci-vbi=vbf-vcf

would i be using theses? for the second equation i divided out mass and the 1/2 and rearranged a bit

The first, yes, and we already know that the initial velocities are zero.
The second equation doesn't look right. I doesn't seem to be related to energy.
Oh, and it's too early to divide out mass or the 1/2. First we need to relate it to the given 9 J of energy.

BvU said:
He doesn't tell you how much of the 9 J is converted to kinetic energy, but I guess you should assume 100%. So the crate comes away undented and undamaged.

I don't see how it could ever be 100%. ;)
Instead I'm assuming we're only given the part of the energy that is converted to mechanical energy. That is, I think the word "mechanical" was accidentally omitted in the problem statement.
 
emily081715 said:
for the second equation i divided out mass
That is not very wise: the mass of the crate is quite different from the mass of the block.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top